Day 11: Plutonian Pebbles

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FAQ

  • Ananace@lemmy.ananace.dev
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    16 days ago

    And now we get into the days where caching really is king. My first attempt didn’t go so well, I tried to handle the full list result as one cache step, instead of individually caching the result of calculating each stone per step.

    I think my original attempt is still calculating at home, but I finished up this much better version on the trip to work.
    All hail public transport.

    C#
    List<long> stones = new List<long>();
    public void Input(IEnumerable<string> lines)
    {
      stones = string.Concat(lines).Split(' ').Select(v => long.Parse(v)).ToList();
    }
    
    public void Part1()
    {
      var expanded = TryExpand(stones, 25);
    
      Console.WriteLine($"Stones: {expanded}");
    }
    public void Part2()
    {
      var expanded = TryExpand(stones, 75);
    
      Console.WriteLine($"Stones: {expanded}");
    }
    
    public long TryExpand(IEnumerable<long> stones, int steps)
    {
      if (steps == 0)
        return stones.Count();
      return stones.Select(s => TryExpand(s, steps)).Sum();
    }
    Dictionary<(long, int), long> cache = new Dictionary<(long, int), long>();
    public long TryExpand(long stone, int steps)
    {
      var key = (stone, steps);
      if (cache.ContainsKey(key))
        return cache[key];
    
      var result = TryExpand(Blink(stone), steps - 1);
      cache[key] = result;
      return result;
    }
    
    public IEnumerable<long> Blink(long stone)
    {
      if (stone == 0)
      {
        yield return 1;
        yield break;
      }
      var str = stone.ToString();
      if (str.Length % 2 == 0)
      {
        yield return long.Parse(str[..(str.Length / 2)]);
        yield return long.Parse(str[(str.Length / 2)..]);
        yield break;
      }
      yield return stone * 2024;
    }