Day 2: Cube Conundrum
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FAQ
- What is this?: Here is a post with a large amount of details: https://programming.dev/post/6637268
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My (awful) Python solves. Much easier than day 1’s, although I did run into an issue with trimming whitespace characters with my approach (Game 96 wouldn’t flag properly).
Part 1
with open('02A_input.txt', 'r') as file: data = file.readlines() possibleGames=[] for game in data: # Find Game number game = game.removeprefix("Game ") gameNumber = int(game[0:game.find(":")]) # Break Game into rounds (split using semicolons) game=game[game.find(":")+1:] rounds=game.split(";") # For each round, determine the maximum number of Red, Blue, Green items shown at a time rgb=[0,0,0] for round in rounds: combos=round.split(",") for combo in combos: combo=combo.strip() number=int(combo[0:combo.find(" ")]) if combo.endswith("red"): if number>rgb[0]: rgb[0]=number elif combo.endswith("green"): if number>rgb[1]: rgb[1]=number elif combo.endswith("blue"): if number>rgb[2]: rgb[2]=number # If Red>12, Green>13, Blue>14, append Game number to possibleGames if not (rgb[0]>12 or rgb[1]>13 or rgb[2]>14): possibleGames.append(gameNumber) print(sum(possibleGames))
Part 2
with open('02A_input.txt', 'r') as file: data = file.readlines() powers=[] for game in data: # Find Game number game = game.removeprefix("Game ") # Break Game into rounds (split using semicolons) game=game[game.find(":")+1:] rounds=game.split(";") # For each round, determine the maximum number of Red, Blue, Green items shown at a time # Note: This could be faster, since we don't need to worry about actual rounds rgb=[0,0,0] for round in rounds: combos=round.split(",") for combo in combos: combo=combo.strip() number=int(combo[0:combo.find(" ")]) if combo.endswith("red"): if number>rgb[0]: rgb[0]=number elif combo.endswith("green"): if number>rgb[1]: rgb[1]=number elif combo.endswith("blue"): if number>rgb[2]: rgb[2]=number # Multiple R, G, B to find the "power" of the game # Append Power to the list powers.append(rgb[0]*rgb[1]*rgb[2]) print(sum(powers))