cm0002@lemmy.world to Comic Strips@lemmy.world · 3 months agoPerfectly balanced, as all things should be.lemmy.mlimagemessage-square41linkfedilinkarrow-up1600arrow-down111cross-posted to: comics@lemmy.ml
arrow-up1589arrow-down1imagePerfectly balanced, as all things should be.lemmy.mlcm0002@lemmy.world to Comic Strips@lemmy.world · 3 months agomessage-square41linkfedilinkcross-posted to: comics@lemmy.ml
minus-squareCompassRedlinkfedilinkarrow-up3·3 months agoInteresting. I think it isn’t unital either otherwise Ω=0. 0=Ω+Ω=Ω+ΩΩ=Ω(1+Ω)=ΩΩ=Ω
minus-squareLeate_Wonceslace@lemmy.dbzer0.comlinkfedilinkEnglisharrow-up1·1 month agoSomeone else had the same observation, but it is unital. Keep in mind that it isn’t associative; you can’t pull out the Omega like that.
minus-squareCompassRedlinkfedilinkarrow-up1·1 month agoThe definition I’m aware of for non associative algebras has them distributive by default, so I believe the chain of equations is valid.
Interesting. I think it isn’t unital either otherwise Ω=0.
0=Ω+Ω=Ω+ΩΩ=Ω(1+Ω)=ΩΩ=Ω
Someone else had the same observation, but it is unital. Keep in mind that it isn’t associative; you can’t pull out the Omega like that.
The definition I’m aware of for non associative algebras has them distributive by default, so I believe the chain of equations is valid.