This was a rare moment where I actually had to think to find it. Can you?
Screenshot is from a solver I found online because I didn’t think to take a screenshot until I already opened the safe square.
This was a rare moment where I actually had to think to find it. Can you?
Screenshot is from a solver I found online because I didn’t think to take a screenshot until I already opened the safe square.
The corner of 1,2,4 on the left must be a bomb.
In the bottom gap, either side of the 1 being a bomb causes the 1,2,4 corner to be a bomb.
If the bomb is right of the 1, then the square above and below the 4 must be bombs because of the 2.
If the bomb is to the left of 1, the 2,2,3,3 forces one of the squares below the second 2 to be a bomb, which means the square below the 4 must be safe, so the square above 4 must be a bomb.
If the bomb is to the left of the one, there could still be another bomb directly next to it, no?
No, the 3 below the two 1s has a shared partner with the 2 to it’s left. So because it has a bomb directly above it, it must have one more below it. Therefore the space under the 4 would be empty and the space above it would have to be a bomb for the upper 2.
Got it now, you’re very right. I didn’t evaluate that 3 correctly at all.